Question

**Potassium nitrate has a lattice energy of -163.8
kcal/mol and a heat of hydration of -155.5 kcal/mol.**

How much potassium nitrate has to dissolve in water to absorb 104 kJ of heat?

Express your answer using two significant figures.
**Answer in kg**

Answer #1

net absorbtion of heat = -155.5 + 163.8 = 8.3 kcal/mol

1 mole of KNO3 absorbs 8.3 kcal = 8.3 * 4.184 kj

34.7272 kJ of heat is absorbed by 101.1 g of KNO3

104 kJ of heat is absorbed by = 101.1 * (104 / 34.7272) g of KNO3

= 302.771 g of KNO3

= 0.3028 kg of KNO3

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol. How much potassium
nitrate (in kg) has to dissolve in water to absorb 100 kJ of
heat?

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol. How much potassium nitrate
has to dissolve in water to absorb 102 kJ of heat? There are 4.184
kJ/kcal. Also note the answer is to be reported in kg.

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol.
Question:
How much potassium nitrate has to dissolve in water to absorb
109 kJ of heat? There are 4.184 kJ/kcal. Also note the answer is to
be reported in kg.

Potassium nitrate has a lattice energy of -163.8 kcal/mol and a
heat of hydration of -155.5 kcal/mol
1.How much potassium nitrate has to dissolve in water to absorb
107 kJ of heat? There are 4.184 kJ/kcal. Also note the answer is to
be reported in kg.

Potassium nitrate has
a lattice energy of -163.8 kcal/mol and a heat of hydration of
-155.5 kcal/mol. How much potassium nitrate has to dissolve in
water to absorb 1.00x102 kJ of heat?
Provide your
answer: numberE^n, remember to watch for sig. figs.

Sodium nitrate has a lattice energy of -2.48 x 10^2 kJ/mol, and
a heat of hydration of -234 kJ/mol.
Determine how much heat is evolved or absorbed when 16.5 g of
sodium nitrate completely dissolves in water?

Potassium perchlorate (KClO4) has a lattice energy of -599
kJ/mol and a heat of hydration of -548 kJ/mol.
A) Find the heat of solution for potassium perchlorate when 10.2
g of potassium perchlorate is dissolved with enough water to make
118.5 mLof solution.

Sodium hydroxide (NaOH) has a lattice energy of -887 kJ/mol and
a heat of hydration of -932 kJ/mol. How much solution could be
heated to boiling by the heat evolved by the dissolution of 28.0 g
of NaOH? (For the solution, assume a heat capacity of 4.0 J/g⋅∘C,
an initial temperature of 25.0 ∘C, a boiling point of 100.0 ∘C, and
a density of 1.05 g/mL.)

Lattice energy for LiF(s) = -1047 kJ/mol
Enthalpy of hydration for Li+(g) = -536 kJ/mol
Enthalpy of hydration for F–(g) = -502 kJ/mol
Determine the enthalpy of solution for LiF(s), using the data
provided.

Using the thermochemical data and an estimated value of -2235.2
kJ/mol for the lattice energy for potassium oxide, calculate the
value for the second electron affinity of oxygen
[O− + e- → O2−]. (The answer is 748.5
kJ/mol)
Quantity
Numerical Value
(kJ/mol)
Enthalpy of atomization of K
89
Ionization energy of K
418.8
Enthalpy of formation of solid K2O
-363
Enthalpy of formation of O(g) from O2(g)
249.1
First electron attachment enthalpy of O -141.0

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