Potassium nitrate has a lattice energy of -163.8 kcal/mol and a heat of hydration of -155.5 kcal/mol.
How much potassium nitrate has to dissolve in water to absorb 104 kJ of heat?
Express your answer using two significant figures. Answer in kg
net absorbtion of heat = -155.5 + 163.8 = 8.3 kcal/mol
1 mole of KNO3 absorbs 8.3 kcal = 8.3 * 4.184 kj
34.7272 kJ of heat is absorbed by 101.1 g of KNO3
104 kJ of heat is absorbed by = 101.1 * (104 / 34.7272) g of KNO3
= 302.771 g of KNO3
= 0.3028 kg of KNO3
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