Question

How many air molecules are in a 15.0×12.0×10.0 ft room? Assume atmospheric pressure of 1.00 atm, a room temperature of 20.0 ∘C, and ideal behavior. Volume conversion:There are 28.2 liters in one cubic foot.

Answer #1

V = 15.0×12.0×10.0 ft = 1800ft^{3}

1ft^{3} = 28.2L

V = 1800ft^{3} = 1800*28.2 = 50760L

P = 1atm

T = 20C^{0} = 20 + 273 = 293K

PV = nRT

n = PV/RT

= 1*50760/0.0821*293

= 2110.16molesw

no of moles of air = 2110.16 moles

no of molecule = no of moles * 6.023*10^{23}

= 2110.16*6.023*10^{23}

= 12707.49*10^{23}

= 1.270749*10^{27} molecules >>>> answer

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