Question

How many air molecules are in a 15.0×12.0×10.0 ft room? Assume atmospheric pressure of 1.00 atm, a room temperature of 20.0 ∘C, and ideal behavior. Volume conversion:There are 28.2 liters in one cubic foot.

Answer 1

V = 15.0×12.0×10.0 ft   = 1800ft³

1ft³ = 28.2L

V = 1800ft³ = 1800*28.2 = 50760L

P = 1atm

T = 20C⁰ = 20 + 273 = 293K

PV = nRT

n = PV/RT

   = 1*50760/0.0821*293

= 2110.16molesw

no of moles of air = 2110.16 moles

no of molecule = no of moles * 6.023*10²³

                    = 2110.16*6.023*10²³

                  = 12707.49*10²³

                 = 1.270749*10²⁷ molecules >>>> answer