Question

A tanker truck carrying 6.05×10³ kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solution is 95.0%H2SO4 by mass and has a density of 1.84 g/mL.

Part A

Sodium carbonate (Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to neutralize 6.05×10³ kg of sulfuric acid solution?

Express your answer with the appropriate units.

Answer 1

mass of 95% by mass of sulfuric acid= mass of concentrated sulfuric acid*0.95 = 6.05*1000*0.95= 5747.5 Kg

the reaction between H2SO4 and sodium Carbonate (Na2CO3) is

Na2CO3+ H2SO4-----------> Na2SO4+ H2O+CO2

1 mole of Na2CO3 requires 1 mole of H2SO4 for neutralization. mole=mass/molar mass

for 1 mole, mass= molar mass

molar masses : Na2CO3= 106 and H2SO4= 98

98 kg of H2SO4 requires 106 kg of Na2CO3 as per the reaction

5747.5 kg of H2SO4 requires 5747.5*106/98 kg of Na2CO3=6217 kg of Na2CO3