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A zero order reaction has a rate constant of 0.28 M s-1. How long will it...

A zero order reaction has a rate constant of 0.28 M s-1. How long will it take for the reactant to reach 30% of its original concentration?

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Answer #1

Apply the zeroth rate law equation

[A] = [A0] - kt

[A0] = initial concnetration, A0

[A] = concnetration in time t, assume it is 30% of original so 0.3*A0

k = 0.28 M/s

t = time, in seconds

so

[A] = [A0] - kt

0.3A0 = A0 - (0.28)t

(0.3-1)A0 = -(0.28)t

t = -0.7A0/-0.28 = 2.5*A0

NOTE that since this is zeroth order, you need to know the initial concnetratio value

you may have time in terms of A0; when you plug a number, you get the real time

t =2.5*A0 seconds is the nearest answer

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