Calculate the pH of a solution prepared by dissolving 2.00 g of calcium hydroxide in one liter of water.
molar mass of Ca(OH)2 is 74
volume of solution is 1L
weight of solute is 2gm
molarity = weight of solute /gram molar mass *volume of solution in L
= 2/74 *1
= 0.027 M
Ca(OH)2 -----> Ca+2 + 2OH-1
[OH-] = 2[Ca(OH)2]
= 2*0.027 =0.054 M
POH = -log[OH]
= -log0.054
POH = 1.2676
PH = 14-POH
= 14-1.2676
= 12.7324 >>>> answer
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