Question

Consider the balanced chemical equation shown below:

2 NH3 + 5 F2 ---> N2F4 + 6 HF

1. How many moles of N2F4 form per mole of reaction? (Answer is in mol / mol reaction)

2. If 0.022 moles of HF form, how many moles of reaction have been completed?

.5 was my answer for 1, and .0256 was my answer for 2 - but neither of those are correct.

Answer 1

2NH₃ + 5 F₂ ---> N₂F₄ + 6HF

If you use 1 mole of NH₃ and 1 mole F₂ (limiting reagent is F₂)you will get 0.2 mole of N₂F_4...

If 6 mole HF forms 2 mole of ammonia and 5 mole of F2 have been completed.

hence 0.022 moles of HF forms = 0.022 x 2 /6 = 0.0146 Mole of NH3.

                                                  = 0.022 x 5/6 = 0.0183 Mole of F2 have been completed.