Question

18.3 cm^3 of a pure vapour, at 1.072 atm, and 98.6 °C has a mass of...

18.3 cm^3 of a pure vapour, at 1.072 atm, and 98.6 °C has a mass of 0.0554 g. Calculate the molar mass of the substance.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The vapor pressure of pure liquid water is p*(H2O) = 0.02308 atm. Above an aqueous solution...
The vapor pressure of pure liquid water is p*(H2O) = 0.02308 atm. Above an aqueous solution with 122 g of a non-volatile solute (molar mass 241 g/mol) in 920 g H2O has a vapor pressure of 0.02239 atm. Calculate the activity and the activity coefficient of water in the solution.
2) Vapour Pressure of Solutions of Non-Volatile or Volatile Solutes A) 48.490 g of a non-volatile...
2) Vapour Pressure of Solutions of Non-Volatile or Volatile Solutes A) 48.490 g of a non-volatile solute is dissolved in 455.0 g of water. The solute does not react with water nor dissociate in solution. Assume that the resulting solution displays ideal Raoult's law behaviour. At 40°C the vapour pressure of the solution is 54.453 torr. The vapour pressure of pure water at 40°C is 55.324 torr. Calculate the molar mass of the solute (g/mol). B) Now suppose, instead, that...
An isotonic solution will produce an osmotic pressure of 7.84 atm measured against pure water at...
An isotonic solution will produce an osmotic pressure of 7.84 atm measured against pure water at human body temperature (37.0°C). How many grams of sodium chloride must be dissolved in a liter of water to produce an isotonic solution? (molar mass NaCl = 58.44 g/mol; molar mass H2O = 18.01 g/mol)
1.) .9720 M aqueous solution of NaCl has a density of 1.03625g/cm^3 at 25 C, Calculate...
1.) .9720 M aqueous solution of NaCl has a density of 1.03625g/cm^3 at 25 C, Calculate the molality of the solution. ( you will also need the density of pure water at the 25C which equals .997044 g/cm^3) 2.) Calculate the apparent molar volume of the above solution. 3.) What quantities will be obtained in a plot of apparent molar volume vs the square root of the molality? 4.) How will these quantities be used to determine the partial volume...
An unknown gas at 57.1 ∘C and 1.10 atm has a molar mass of 44.10 g/mol....
An unknown gas at 57.1 ∘C and 1.10 atm has a molar mass of 44.10 g/mol. Assuming ideal behavior, what is the density of the gas?
An unknown gas at 33.1 °C and 1.05 atm has a molar mass of 30.07 g/mol....
An unknown gas at 33.1 °C and 1.05 atm has a molar mass of 30.07 g/mol. Assuming ideal behavior, what is the density of the gas?
Pure 235U has a molar mass of 235.0439299 g. What is the mass of a single...
Pure 235U has a molar mass of 235.0439299 g. What is the mass of a single 235U atom in grams?
A)Calculate the density of NO2 gas at 0.990 atm and 36 ∘C. B)Calculate the molar mass...
A)Calculate the density of NO2 gas at 0.990 atm and 36 ∘C. B)Calculate the molar mass of a gas if 2.50 g occupies 0.865 L at 680 torr and 36 ∘C.
A benzene-toluene solution with xbenz=0.300 has a normal boiling point of 98.6 C. The vapor pressure...
A benzene-toluene solution with xbenz=0.300 has a normal boiling point of 98.6 C. The vapor pressure of pure toluene at 98.6 C is 533 mmHg. What must be the vapor pressure of pure benzene at 98.6 C?
Pure nitrogen at 160°C and 2 atm enters a cylinder whose inner walls are coated with...
Pure nitrogen at 160°C and 2 atm enters a cylinder whose inner walls are coated with naphthalene. The nitrogen flow is turbulent. The Dittus-Boelter relation for turbulent flow heat transfer in a pipe is Nu = 0.023Re^0.8Pr0.4 The velocity through the 6 cm diameter tube is 10 m s-1. (a) Derive an equation relating concentration of naphthalene to tube length; (b) What tube length would be necessary to obtain a naphthalene mole fraction of 0.05 in the exit stream? Additional...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT