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home / study / questions and answers / science / chemistry / if the conversion of 77.0% ferric oxide to iron ... Question If the conversion of 77.0% ferric oxide to iron and oxygen is 95% efficient, what mass of this ferric oxide is required to make 2.50 moles of iron? Comment

Answer 1

2Fe₂O₃------> 4Fe + 3O₂

2 moles        4 moles

2 moles of Fe2O3 gives 4 moles of Fe

2*2.5/4 = 1.25 moles of FeO3 gives 2.5 moles of Fe

But efficient is 95%

1.25*95% = 1.25*95/100 = 1.1875 moles of Fe2O3

mass of Fe2O3 = no of moles * gram molar mass

                       = 1.1875*160 = 190gm

190gm   ---------> 77%

190*100/77 = 246.7 gm of Fe2O3 is required >>> answer