from your predicted the value of the vant hoff factor, calculate the boiling point of a 1.50 m aqueous solution of barium nitrate, Ba(NO3)2? The Kb of water is 0.52C/m.
vant hoff factor for Ba(NO3)2 = 3 ( 1 Ba+2 ion and 2 NO3- ions)
Tb = Kb X molality
= 0.52 X 1.5
= 0.78
Tb = T1 - T0 (T1 = boiling point of solution, T0 = boiling point of water(solvent) T0 = 1000C)
T1 = Tb + T0
= 0.78 + 100
= 100.78 0C
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