Question

Describe the preparation of 1) 3.00 L of 22.0% (w/v) aqueous glycerol (C3H8O3, 92.1 g/mol). Weigh _ g glycerol and add enough water to give a final volume of _ L.

2) 3.00 kg of 22.0% (w/w) aqueous glycerol. Mix _ g glycerol with _ kg water.

3)

3.00 L of 22.0% (v/v) aqueous glycerol.

Dilute _ mL glycerol with enough water to give a final volume of _ L.

Answer 1

Answer – 1) We are given, volume = 3.00 L. aq. glycerol = 22.0 % (w/v)

We know w/v means mass in the volume percent

So, volume = 3.00 L

For 100 mL solution there is 22.0 g of glycerol

So, 3000 mL (3.00 L) = ? g

= 660 g of glycerol

So, Weigh 660 g glycerol and add enough water to give a final volume of 3.00 L.

2) We are given, mass of solution = 3.00 kg.

aq. glycerol = 22.0 % (w/w)

We know w/w means weight by weight

So, mass of solution is 3.00 kg = 3000 g

For 100 g solution there is 22.0 g of glycerol

So, 3000 g = ? g

= 660 g of glycerol

So, Mix 660 g glycerol with 3.00 kg water.

3) We are given, volume = 3.00 L. aq. glycerol = 22.0 % (v/v)

We know v/v means volume by volume

So, volume = 3.00 L = 1000 mL

For 100 mL solution there is 22.0 mL of glycerol

So, 3000 mL = ? mL

= 660 mL of glycerol

So, dilute 660 mL glycerol with enough water to give a final volume of 3.00 L.