Question

A flask containing 456mL of a solution was prepared from solid ammonium chloride(NH4Cl) and water. The molarity of the NH4Cl is 0.895M. What mass of NH4Cl was used to prepare the solution?

Do I just multiply (.895M/L)*(.456L)*(53.4915 g/mol) ?

Answer 1

Yes you need to multiply these numbers.

EXPLANATION :

0.895 molar solutions means that we have 0.895 moles of ammonium chloride (NH₄Cl) in 1L of solution.

1 litre solution -----> 0.895 mole NH₄Cl

The volume of given flask = 456mL or 0.456L ( 1L =1000mL)

Moles of NH₄Cl in 0.456L of solution = (0.895)*(0.456)

Moles*Molar mass = Given mass

Molar mass of NH₄Cl = 14.0067 + 1.0079*4 + 35.43 = 53.49g/mol

Given mass of NH₄Cl in solution = (0.895)*(0.456)*(53.49)

= 21.83g