Question

For the following chemical reaction, how many moles of silver chromate will be produced from 102 g of silver nitrate?

2AgNO₃+Na₂CrO₄ ----> Ag₂CrO₄+2NaNO₃

Answer 1

Step(l)

Molecular mass of AgNO3 = 170g/mol

Number of moles of AgNO3 = (mass of AgNO3)÷(moleculem mass of AgNO3)

Number of moles of AgNO3 = (102g)÷(170g/mol)

Number of moles of AgNO3= 0.6mol

Step(ll)

From the stoichiometry of reaction

2mole silver nitrate form 1mole silver chromate

So 1mole silver nitrate form 1/2 mole silver chromate

Hence

0.6 mole silver nitrate form (1/2)×0.6mole silver chromate

Number of silver chromate=(1/2)×0.6mol

Number of silver chromate = 0.3mole