Question

Report how much glucose was present before we started fermentation (this is 800 mg/dL for everybody because we just did one representative test). Use this number to calculate the maximum theoretical mass (in grams) of ethanol that we could have produced in the fermentation. In other words, given that one molecule of glucose produces two molecules of ethanol, calculate how many grams of ethanol could be produced if every single glucose molecule was converted into two ethanol molecules (this is called the 'theoretical yield). Note that a dL is one tenth of a liter, or 100 mL, and our mixture at that point had a total (liquid) volume of 50 mL, so we had about 400 mg of glucose total.

Using the result from above and our starting mass of corn stover, calculate the 'theoretical yield' of ethanol in terms of liters of (100%) ethanol per metric ton (1000 kg) of corn stover.

Answer 1

We have 400 mg of glucose

C6H12O6 -----------> 2CH3CH2OH + 2CO2

1 mole of glucose produces 2 moles of ethanol

Moles of glucose = mass /molar mass = 400mg / 180 = 2.22 millimoles

Moles of ethanol produced = 2*moles of glucose = 2*2.22 = 4.44 millimoles

Mass of ethanol = molar mass*Moles = 46*4.44millimoles = 202.24 mg

This amount of ethanol is produced ...please convert into desired units

If u want to convert into litres ..we need t know the density of ethanol

Thanking u