Question

Each value below represents a different aqueous solution at 25 °C. Classify each solution as acidic, basic, or neutral.

pH=1.48

pOH=8.54

[H^+]=2.6*10^2

pH=11.68

pOH=5.35

[H^+]=8.7810^-13

[OH^-]=7.7*10^-11

[OH^-]=9.2*10^-3

[H^+]=1.0*10^-7

pOH=7.0

Answer 1

if pH <7 acidic pH >7 basic, pH = 7 nuetral

pH=1.48 = acidic

pOH=8.54

pH + pOH = 14 pH = 14-pOH pH = 14-8.54 = 5.46 acidic

[H^+]=2.6*10^2

pH = -log[H+] =-log [2.6 x 10² ] = 2.41 = acidic

pH=11.68 = basic

pOH=5.35

pH + pOH = 14 pH = 14-pOH pH = 14-5.35 =8.65 basic

[H^+]=8.7810^-13

pH = -log[H+] =-log [8.78 x 10^-13 ] = 12.05 = basic

[OH^-]=7.7*10^-11

pOH = -log [7.7*10^-11] = 10.1135

pH + pOH = 14 pH = 14- 10.1135 = 3.88 acidic

[OH^-]=9.2*10^-3

pOH = -log [9.2*10^-3] = 2.03

pH + pOH = 14 pH = 14- 2.03 =11 basic

[H^+]=1.0*10^-7

pH = -log[H+] =-log [1.0*10^-7 ] = 7 = nuetral

pOH=7.0

pH + pOH = 14 pH = 14-7 = 7 nuetral