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the equilibrium constant Kc for the reaction c--> d+e is 5.30*10^-5. the initial composition of the...

the equilibrium constant Kc for the reaction c--> d+e is 5.30*10^-5. the initial composition of the reaction is [c]=[D]=[E]=1.3*10^-3what is the equilibrium concentration c,d,e

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Answer #1

The reaction is:

c <-------> d + e

initial: 1.3*10^-3 1.3*10^-3 1.3*10^-3

equi: 1.3*10^-3-x 1.3*10^-3+x 1.3*10^-3+x

The expression for rate of reaction= d*e/c^2

5.30*10^-5=( 1.3*10^-3+x)*( 1.3*10^-3+x)/(1.3*10^-3-x)

On solving, the value of x= -1.69*10^-3 and  -0.95*10^-3

x cannot be greater than initial value.

so correct value for x is -0.95*10^-3

Equilibrium conc of c ==1.3*10^-3-x==1.3*10^-3 +0.95*10^-3

=2.25*10^-3

Equilibrium conc of d ==1.3*10^-3-x==1.3*10^-3 -0.95*10^-3

=0.35*10^-3

Equilibrium conc of e ==1.3*10^-3-x==1.3*10^-3 -0.95*10^-3

=0.35*10^-3

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