Question

For 1 kg of CO, calculate the hydrogen required and the resulting products for ethylene (C2H4), isopropanol (C3H8O), and pentane (C5H12) for Fischer-Tropsch synthesis.

Answer 1

1 Kg CO = 1000 / 28 = 35.71 Mole

2CO + 4H₂ -------> C₂H₄ + 2H₂O

35.71 Mole of CO need (35.71 x 2) 71.42 Mole of hydrogen

71.42 Mole of hydrogen = 71.42 x 2.016 = 143.98 gm of H₂ Need

isopropanol (C3H8O)

3CO + 6H₂ -------> C₃H₈O + 2H₂O

35.71 Mole of CO need (35.71 x 2) 71.42 Mole of hydrogen

71.42 Mole of hydrogen = 71.42 x 2.016 = 143.98 gm of H₂ Need

pentane (C5H12)

5CO + 11H₂ -------> C₅H₁₂ + 5H₂O

35.71 Mole of CO need (35.71 x 11/5) 78.56 Mole of hydrogen

78.56 Mole of hydrogen = 71.42 x 2.016 = 158.38 gm of H₂ Need