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calculate the number of atoms of oxygen in 235.67g of ZnCO3

calculate the number of atoms of oxygen in 235.67g of ZnCO3

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Answer #1

1 mole of ZnCO3 contains 3 mole of oxygens

number of moles of ZnCO3 = 235.67/125.39

                                                 = 1.8795 moles

number of oxygen atoms = 1.8795 * 3 * 6.023 * 10 ^23

                                             = 3.3961 * 10^24 atoms of oxygen

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