If 56.3 mL of silver nitrate solution reacts with excess potassium chloride solution to yield 0.273 g of precipitate, what is the molarity of silver ion in the original solution?
____M
We know molarity of solution is defined as number of moles of solute dissolved per litre of solution.Molarity is the property which gives concentration o particular species in solution.
From above question we can infer information that Excess KCl is being dissolved in AgNO3 solution to yield 0.273 g of precipitate.
So here as KCl is in excess so remaining of it will get precipiated
Hence number of moles of KCl=0.273/74.5=3.66*10-3
Volume of AgNO3 solution=56.3ml=0.0563 litres
So Molarity=3.66*10-3/0.0563=0.065 M
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