A 2.60 M aqueous solution of LiCl has a density of 1.0582 g/mL. If the total mass of the solution is 59.0 g, what masses of solute and solvent are present?
density of solution = 1.0582 g/mL
mass of solution = 59.0 g
use:
density = mass / volum
1.0582 g/mL = 59.0 g / volume
volume = 55.76 mL
volume , V = 55.76 mL
= 5.576*10^-2 L
number of mol,
n = Molarity * Volume
= 2.6*0.05576
= 0.145 mol
Molar mass of LiCl,
MM = 1*MM(Li) + 1*MM(Cl)
= 1*6.968 + 1*35.45
= 42.418 g/mol
mass of LiCl,
m = number of mol * molar mass
= 0.145 mol * 42.418 g/mol
= 6.15 g
This is mass of solute
mass of solvent = mass of solution - mass of solute
= 59.0 g - 6.15 g
= 52.85 g
Answer:
solute : 6.15 g
solvent : 52.85 g
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