An ethylene glycol solution contains 24.6 g of ethylene glycol (C2H6O2) in 96.6 mL of water. (Assume a density of 1.00 g/mL for water.) Part ADetermine the freezing point of the solution. Part B Determine the boiling point of the solution.
weight of water = volue *density
= 96.6*1 = 96.6gm
molality = mass of solute*1000/gram molar mass of solute *weight of solvent
= 24600/5969.2 = 4.12 m
Tf = m*Kf
kf of water =-1.86g/mole
Tf = 4.12*-1.86 = -7.66C0
freezin point = -7.66C0
Tb = m*Kb
boiling point = 100+0.495 = 100.495C0
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