Question

Formula for mole fraction of ligand X_L = moles ligand/(moles metal + moles ligand)

en (M)	Ni2+ (M)	Xen	en (mL)	Ni2+ (mL)	en (L)	Ni2+ (L)	en (mol)	Ni2+ (mol)
0.4	0.4	0.0	0.0	10.0	0.0	0.010	0.0	0.0040
		0.3
		0.4
		0.5
		0.6
		0.7
		0.8
		0.9
		1.0

Using prepared solutions of NiSO₄.6H₂O (0.4 M) and ethylenediamine (0.4 M) and assuming a final total solution volume of 10 mL, determine the milliliters of NiSO₄.6H₂O and ethylenediamine you would combine to prepare solutions with the final mole fraction of ligand: 0.0, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9 and 1.0.

please show at work for at least one solution.

Answer 1

en (M)	Ni2+ (M)	Xen	en (mL)	Ni2+(mL)	en (L)	Ni2+(L)	en(mol)	Ni2+(mol)
0.4	0.4	0.0	0.0	10.0	0.0	0.010	0.0	0.004
0.4	0.4	0.3	3.0	7.0	0.003	0.007	0.0012	0.0028
0.4	0.4	0.4	4.0	6.0	0.004	0.006	0.0016	0.0024
0.4	0.4	0.5	5.0	5.0	0.005	0.005	0.0020	0.0020
0.4	0.4	0.6	6.0	4.0	0.006	0.004	0.0024	0.0016
0.4	0.4	0.7	7.0	3.0	0.007	0.003	0.0028	0.0012
0.4	0.4	0.8	8.0	2.0	0.008	0.002	0.0032	0.0008
0.4	0.4	0.9	9.0	1.0	0.009	0.001	0.0036	0.0004
0.4	0.4	1.0	10.0	0.0	0.010	0.0	0.0040	0.0