Question

# Formula for mole fraction of ligand XL = moles ligand/(moles metal + moles ligand) en (M)...

Formula for mole fraction of ligand XL = moles ligand/(moles metal + moles ligand)

 en (M) Ni2+ (M) Xen en (mL) Ni2+ (mL) en (L) Ni2+ (L) en (mol) Ni2+ (mol) 0.4 0.4 0.0 0.0 10.0 0.0 0.010 0.0 0.0040 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0

Using prepared solutions of NiSO4.6H2O (0.4 M) and ethylenediamine (0.4 M) and assuming a final total solution volume of 10 mL, determine the milliliters of NiSO4.6H2O and ethylenediamine you would combine to prepare solutions with the final mole fraction of ligand: 0.0, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9 and 1.0.

please show at work for at least one solution.

#### Homework Answers

Answer #1

 en (M) Ni2+ (M) Xen en (mL) Ni2+(mL) en (L) Ni2+(L) en(mol) Ni2+(mol) 0.4 0.4 0.0 0.0 10.0 0.0 0.010 0.0 0.004 0.4 0.4 0.3 3.0 7.0 0.003 0.007 0.0012 0.0028 0.4 0.4 0.4 4.0 6.0 0.004 0.006 0.0016 0.0024 0.4 0.4 0.5 5.0 5.0 0.005 0.005 0.0020 0.0020 0.4 0.4 0.6 6.0 4.0 0.006 0.004 0.0024 0.0016 0.4 0.4 0.7 7.0 3.0 0.007 0.003 0.0028 0.0012 0.4 0.4 0.8 8.0 2.0 0.008 0.002 0.0032 0.0008 0.4 0.4 0.9 9.0 1.0 0.009 0.001 0.0036 0.0004 0.4 0.4 1.0 10.0 0.0 0.010 0.0 0.0040 0.0
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