In a first-order process a blue dye reacts to form a purple dye. The amount of blue at the end of 1hr is 480g and at the end of 3hr is 120g. Graphically estimate the amount of blue present initially.
In a first-order process a blue dye reacts to form a purple dye. The amount of blue at the end of 1hr is 480g and at the end of 3hr is 120g. Graphically estimate the amount of blue present initially.
assume t = 1h, is actually initial time, so
A0 = 480 g at t = 0
then, Afinal = 120 g at t = 3-1 = 2
estimate K
ln(A) = ln(A0) - kt
ln(120) = ln(480) - k(2)
k = (ln(120 - ln(480) ) /(-2)
k = 0.6931
now
at t = -1
ln(A) = ln(480) - 0.6931(-1)
A = exp(ln(480) - 0.6931(-1))
A = 959.95 g initially at t = -1 . i.e. t = 0 hours
Get Answers For Free
Most questions answered within 1 hours.