Question

Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate the amount of Ga(s) that can be deposited from a Ga(III) solution by a current of 0.560 A that flows for 80.0 min.

Answer 1

According to Faraday's first law

m = (ECt ) / 96500

Where

m = mass of metal deposited = ?

E = equivalent weight of Ga = Molecular weight / valancy

                                         = 69.7 / 3

                                         = 23.23

C = current = 0.560 A

t = time taken = 80.0 min

   = 80.0 min x ( 60 s/min)

   = 4800 s

Plug the values we get

m = ( 23.23 x 0.560 x 4800 ) / 96500

   = 0.65 g

Therefore the mass of Ga deposited is 0.65 g