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For a certain reaction, Kc = 3.33×10−2 and k f = 1.30×10−2 M−2⋅s−1 M − 2...

For a certain reaction, Kc = 3.33×10−2 and k f = 1.30×10−2 M−2⋅s−1 M − 2 ⋅ s − 1 . Calculate the value of the reverse rate constant, kr , given that the reverse reaction is of the same molecularity as the forward reaction.

For a different reaction, Kc = 2.66×104, kf=9.40×105s−1kf=9.40×105s−1 , and kr= 35.3 s−1s−1 . Adding a catalyst increases the forward rate constant to 2.25×108 s−1s−1 . What is the new value of the reverse reaction constant, kr

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