What mass of water is contained in 160 grams of 22.0% (m/v) KCl solution (Density of solution: 1.1 g/mL)?
please show full solution, (Indicate your answers to two digits after the decimal)
Given,
Mass of KCl solution = 160 grams
m/v percent of KCl = 22.0 %
Density of solution = 1.1 g/mL
Firstly calculating the volume of the solution from the given mass of solution and density of the solution,
= 160 grams KCl solution x ( 1 mL /1.1 g)
= 145.45 mL solution.
Now, calculating the mass of solute(KCl) present in the solution from the m/v percent and volume of solution.
= (22.0 /100 ) x 145.45 mL
= 32 grams KCl is present in 145.45 mL of solution.
Now, We know.
Mass of solution = 160 grams
Mass of solute(KCl) = 32 grams
Thus,
Mass of solution = Mass of solute(KCl) + Mass of solvent(water)
Rearranging the formula,
Mass of solvent(water) = Mass of solution - Mass of solute(KCl)
Mass of solvent(water) = 160 g - 32 g
Mass of solvent(water) = 128.00 g
Thus, 1.28 x 102 g water is contained in 160 grams of 22.0% (m/v) KCl solution.
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