If a Neanderthal excreted 500mL of urine into the ocean 50,000 years ago,how many molecules in 500mL of water you drink today are from that urine,and assume complete mixing of the waters of Earth over 50,000 years.
Volume of ocean = 3.5*10^8 mi^3 approx
change to mL (factor is 4.171428*10^15)
V = 1.46*10^24 mL are present
then
conver cooncentrations
500 mL urine / ( 1.46*10^24 mL ocean) --> 3.42*10^-22 mL per 1 mL of ocean (simply inver ratios)
since we have 500 mL
then
(3.42*10^-22 mL) per mL of water * 500 mL of water
3.42*10^-22)(500) =1.71 *10^-19 mL
the density of water (assume)
D = 1 g/mL
so
1.71*10^-19 g of water
change to mol so
mol = mass/MW
MW of water = 18 g/mol
1.71*10^-19 g ---> 1.71*10^-19)/(18) = 9.5*10^-21 mol
so
1 mol = 6.022*10^23 molecules
molecules in sample = (6.022*10^23) * (9.5*10^-21) = 5720.9 molecules will be found
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