Question

500 g of acetone, C2H60, is dissolved into 500 g of water, H2O, at 25 degrees C. What is the vapor pressure of the entire solution? vp water= 24 torr vp acetone= 223 torr

Answer 1

no of moles of acetone = W/G.M.Wt

                               n_A = 500/58 = 8.62 moles

no of moles of water n_B = 500/18 = 27.7 moles

mole fraction of X_A   = n_A/n_A+n_B

                             = 8.62/8.62*27.7 = 0.236

mole fraction of X_B = 1-X_A

                           = 1-0.236 = 0.764

P   = P_AX_A + P_BX_B

   = 233*0.236 + 24*0.764

=     54.988 +18.336 = 73.324 torr ...total pressure >>>> answer