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A solution is made by dissolving 0.579 mol of nonelectrolyte solute in 891 g of benzene....

A solution is made by dissolving 0.579 mol of nonelectrolyte solute in 891 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution.

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Answer #1

molality = moles of solute / mass of solvent (kg)

               = 0.579 / 0.891

              = 0.65 m

Solvent Boiling Point (°C) Kb(°C kg/mol) Freezing Point (°C) Kf (°C kg/mol)
Benzene 80.1 2.65 5.5 –5.12

Tf = kf x m

To - Tf = Kf x m

5.5 - Tf = 5.12 x 0.65

Tf = 2.17 oC

Tf = kf x m

Tb- To = Kb x m

Tb - 80.1 = 2.65 x 0.65

Tb = 81.82 oC

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