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A line in the emissions spectrum of an atom accurs at a wavelength of (6.27*10^2)mm. What...

A line in the emissions spectrum of an atom accurs at a wavelength of (6.27*10^2)mm. What is the energy difference between the two energy levels involved in this emission

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Answer #1

ANSWER.given data wave length=6.27x102 mm=6.27x10-1m. energy differenceE=hc/ (where h=6.627x10-34 J.s c=3x108 m/s) substituting the planck's constant h and speed of light c in the above formula, E =(6.627x10-34 J.s x3x108 m/s)/6.27x10-1m E=(19.88x10-25) /6.27=3.17x10-25J

Energy difference= 3.17x10-25J

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