Question

Determine the volume in mL of 0.43 M HClO_{4}(aq) needed
to reach the half-equivalence (stoichiometric) point in the
titration of 24 mL of 0.32 M
CH_{3}CH_{2}NH_{2}(aq)(aq). The
K_{b} of ethylamine is 6.5 x 10^{-4}.

CORRECT ANSWER: 9

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Answer #1

Determine the volume in mL of 0.12 M NaOH(aq) needed to reach
the equivalence (stoichiometric) point in the titration of 27 mL of
0.16 M HF(aq). The Ka of HF is 7.4 x 10-4

Determine the volume in mL of 0.15 M NaOH(aq) needed to reach
the equivalence (stoichiometric) point in the titration of 48 mL of
0.12 M HF(aq). The Ka of HF is 7.4 x 10-4.

1. Determine the volume in mL of 0.2 M NaOH(aq) needed
to reach halfway to the equivalence (stoichiometric) point in the
titration of 31 mL of 0.21 M propanoic acid(aq). The Ka
of propanoic acid is 1.3 x 10-5.
2. Determine the pH at the equivalence (stoichiometric)
point in the titration of 26 mL of 0.15 M
(CH3)2NH(aq) with 0.2 M HCl(aq). The
Kbof (CH3)2NHis 5.4 x
10-4.
Please Help me these questions!

1)Calculate the pH during the titration of 20.00 mL of 0.1000 M
trimethylamine, (CH3)3N(aq), with 0.1000 M
HNO3(aq) after 19.5 mL of the acid have been added.
Kb of trimethylamine = 6.5 x 10-5.
2)Determine the volume in mL of 0.13 M KOH(aq) needed to reach
the half-equivalence (stoichiometric) point in the titration of 42
mL of 0.23 M C6H5OH(aq). The Ka of
phenol is 1.0 x 10-10.
Please explain

Find the pH of the equivalence point and the volume (mL) of
0.150M HCl needed to reach the equivalence point in the titration
of 21.8 mL of 1.11 M CH3NH2. Confused how to approach this with out
the Ka/Kb values given.

Determine the pH at the equivalence (stoichiometric) point in
the titration of 25 mL of 0.29 M HClO(aq) with 0.17 M NaOH(aq). The
Ka of HClO is 2.3 x 10-9.
Answer in scientific notation please! Thank you!!

Find the pH of the equivalence point and the volume (mL) of
0.0358 M KOH needed to reach the equivalence point in the titration
of 23.4 mL of 0.0390 M HNO2.

1. Calculate the pH during the titration of 20.00 mL of 0.1000 M
C6H5COOH(aq) with 0.1000 M NaOH(aq) after 19
mL of the base have been added. Ka of benzoic acid = 6.5
x 10-5.
2. Determine the volume in mL of 0.15 M KOH(aq) needed to reach
the half-equivalence (stoichiometric) point in the titration of 35
mL of 0.18 M HNO2(aq). The Ka of nitrous acid
is 7.1 x 10-4.

1)Calculate the pH during the titration of 20.0 mL of 0.25 M HBr
with 0.25 M KOH after 20.7 mL of the base have been added.
2)Calculate the pH during the titration of 40.00 mL of 0.1000 M
HNO2(aq) with 0.1000 M KOH(aq) after 24 mL of the base
have been added. Ka of nitrous acid = 7.1 x
10-4.
3)Calculate the pH during the titration of 20.00 mL of 0.1000 M
trimethylamine, (CH3)3N(aq), with 0.2000 M
HCl(aq) after 4.5...

1. Determine the pH at the equivalence (stoichiometric) point in
the titration of 28 mL of 0.17 M H3BO3(aq)
with 0.11 M NaOH(aq). The Ka of
H3BO3 is 5.8 x 10-10.

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