Question

Determine the volume in mL of 0.43 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point...

Determine the volume in mL of 0.43 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 24 mL of 0.32 M CH3CH2NH2(aq)(aq). The Kb of ethylamine is 6.5 x 10-4.

CORRECT ANSWER: 9

Please show work on how to get that answer!

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Determine the volume in mL of 0.12 M NaOH(aq) needed to reach the equivalence (stoichiometric) point...
Determine the volume in mL of 0.12 M NaOH(aq) needed to reach the equivalence (stoichiometric) point in the titration of 27 mL of 0.16 M HF(aq). The Ka of HF is 7.4 x 10-4
Determine the volume in mL of 0.15 M NaOH(aq) needed to reach the equivalence (stoichiometric) point...
Determine the volume in mL of 0.15 M NaOH(aq) needed to reach the equivalence (stoichiometric) point in the titration of 48 mL of 0.12 M HF(aq). The Ka of HF is 7.4 x 10-4.
1. Determine the volume in mL of 0.2 M NaOH(aq) needed to reach halfway to the...
1. Determine the volume in mL of 0.2 M NaOH(aq) needed to reach halfway to the equivalence (stoichiometric) point in the titration of 31 mL of 0.21 M propanoic acid(aq). The Ka of propanoic acid is 1.3 x 10-5. 2. Determine the pH at the equivalence (stoichiometric) point in the titration of 26 mL of 0.15 M (CH3)2NH(aq) with 0.2 M HCl(aq). The Kbof (CH3)2NHis 5.4 x 10-4. Please Help me these questions!
1)Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.1000...
1)Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.1000 M HNO3(aq) after 19.5 mL of the acid have been added. Kb of trimethylamine = 6.5 x 10-5. 2)Determine the volume in mL of 0.13 M KOH(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 42 mL of 0.23 M C6H5OH(aq). The Ka of phenol is 1.0 x 10-10. Please explain
Find the pH of the equivalence point and the volume (mL) of 0.150M HCl needed to...
Find the pH of the equivalence point and the volume (mL) of 0.150M HCl needed to reach the equivalence point in the titration of 21.8 mL of 1.11 M CH3NH2. Confused how to approach this with out the Ka/Kb values given.
Determine the pH at the equivalence (stoichiometric) point in the titration of 25 mL of 0.29...
Determine the pH at the equivalence (stoichiometric) point in the titration of 25 mL of 0.29 M HClO(aq) with 0.17 M NaOH(aq). The Ka of HClO is 2.3 x 10-9. Answer in scientific notation please! Thank you!!
Find the pH of the equivalence point and the volume (mL) of 0.0358 M KOH needed...
Find the pH of the equivalence point and the volume (mL) of 0.0358 M KOH needed to reach the equivalence point in the titration of 23.4 mL of 0.0390 M HNO2.
1. Calculate the pH during the titration of 20.00 mL of 0.1000 M C6H5COOH(aq) with 0.1000...
1. Calculate the pH during the titration of 20.00 mL of 0.1000 M C6H5COOH(aq) with 0.1000 M NaOH(aq) after 19 mL of the base have been added. Ka of benzoic acid = 6.5 x 10-5. 2. Determine the volume in mL of 0.15 M KOH(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 35 mL of 0.18 M HNO2(aq). The Ka of nitrous acid is 7.1 x 10-4.
1)Calculate the pH during the titration of 20.0 mL of 0.25 M HBr with 0.25 M...
1)Calculate the pH during the titration of 20.0 mL of 0.25 M HBr with 0.25 M KOH after 20.7 mL of the base have been added. 2)Calculate the pH during the titration of 40.00 mL of 0.1000 M HNO2(aq) with 0.1000 M KOH(aq) after 24 mL of the base have been added. Ka of nitrous acid = 7.1 x 10-4. 3)Calculate the pH during the titration of 20.00 mL of 0.1000 M trimethylamine, (CH3)3N(aq), with 0.2000 M HCl(aq) after 4.5...
1. Determine the pH at the equivalence (stoichiometric) point in the titration of 28 mL of...
1. Determine the pH at the equivalence (stoichiometric) point in the titration of 28 mL of 0.17 M H3BO3(aq) with 0.11 M NaOH(aq). The Ka of H3BO3 is 5.8 x 10-10.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT