Prepare 1 liter of a 0.250M hypochlorite buffer solution. What volume of 1.5M NaOH must be added to get a buffer with a pH of 8? Ka value for the acid is 3.00 x 10^-8.
My answer is 41.7 mL.
PH = PKa + log[salt]/[Acid]
PH = 8
PKa = -log3*10-8 = 7.5228
8 = 7.5228 + logx/0.25-x
logx/0.25-x = 8-7.5228
logx/0.25-x = 0.4772
x/0.25-x = 100.4772
x/0.25-x = 3
x = 3(0.25-x)
x = 0.1875 moles of NaOH
molarity of NaOH = no of moles/volume in L
1.5 = 0.1875/volume in L
volume in L = 0.1875/1.5 = 0.125L = 125ml
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