Question

C2H2 (g) + 3H2 (g) --> 2CH4 (g) ΔHf:    227                               &n

C2H2 (g) + 3H2 (g) --> 2CH4 (g)

ΔHf:    227                                  -75      (kJ/mol)

S°:    201            131               186      (J/mol K)

At which Kelvin temperature does the reaction switch from being spontaneous to nonspontaneous? (For this question, do not worry about specifying whether it is spontaneous above or below this temperature.)

Homework Answers

Answer #1

C2H2 (g) + 3H2 (g) ---------------> 2CH4 (g)

ΔHrxn = ΔHproducts - ΔHreactants

            = 2 x -75 - (227 + 0)

            = - 377 kJ/mol

ΔSrxn = ΔSproducts - ΔSreactants

           = 2 x 186 - (201 + 3x131)

           = - 222 J/mol K

ΔG = ΔH - T ΔS

for spontaneous reaction ΔG < 0. so

ΔH < T ΔS

T < ΔH/ΔS

   < - 377 x 10^3 / - 222

   < 1698 K

above 1698 K it is spontenous. below this it is non spontenous.

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