Consider the following reaction. A(aq) <---> 2B(aq)? Kc = 1.80 x 10^-6 at 500K If a 4.40 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?
A(aq) <------------------> 2B(aq)
4.40 0
4.4-x 2x
Kc = (2x)^2/4.4 - x
1.80 x 10^-6 = 4x^2/4.4-x
x = 0.00141
[B] = 2x = 2 x 0.00141= 0.0028 M
concentration of B at equilibrium = 0.0028 M
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