Question

The reaction CaCO_3(s) + 2 HCl_(g) CaCl_2(s) + CO_2(g) + H₂O_(l) is at equilibrium. How would this system shift if the volume of the flask in which the reaction is occuring decreased? Briefly explain.

Answer 1

In this given reaction , the equilibrium remain undisturbed when volume of the container decreased. Because of the fact that , the mole number of reactants and products remain same.

Note- according to la chatelier's principle , when volume decreases then equilibrium will shift to that side which have lower number of molecules.

And, when volume increases then equilibrium will shift to that side which have greater number of molecules.

As here the number of molecules on reactant and products both the side same, hence change in volume i.e., decrease in the volume will not affect the equilibrium.