Question

How much energy is contained in 1 mol of γ-ray photons with a wavelength of 2.68×10−5 nm

Answer #1

1. Convert nm to m

1 nm = 10^{-9} m

2.68 x
10^{-5} nm = (2.68 x 10^{-5}) x 10^{-9} m =
2.68 x 10^{-14} m

2. Use formula E=hc/wavelength (where, h = 6.63 x
10^{-34}Js, c = 3 x 10^{8} m/s)

E = { (6.63 x 10^{-34}Js) (3 x 10^{8} m/s) } /
(2.68 x 10^{-14} m)

= 53.31 x 10^{-12}J

3. Convert J to kJ

1 J = 10^{-3}kJ

53.31 x
10^{-12}J = 53.31 x 10^{-12} x 10^{-3}
kJ

= 53.31 x 10^{-15} kJ

4. Multiply by Avogadro's number

(6.02 x 10^{23}) x (53.31 x 10^{-15} kJ)

= 3.21 x 10^{10} kJ

Part A.
How much energy is contained in 1 mol of each of the
following?
γ-ray photons with a wavelength of 2.63×10−5
nm.
_____________ kJ/mol
Part B.
An electron traveling at 5.6×105 m/s has an uncertainty
in its velocity of 1.25×105 m/s .
What is the uncertainty in its position?
Express your answer with the appropriate units.
Δx = __________
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