Question

I have NO idea how to even begin these steps. Data is listed below. Please include...

I have NO idea how to even begin these steps. Data is listed below. Please include formulas and step-by-step process in calculations.

Determining the Effect of Temperature on Reaction Rate:

KI, M: Determinination 1) 0.042 2) 0.042 3) 0.042 4) 0.042

(NH4)2 S2O8, M: Determination 1) 0.021 2) 0.021 3) 0.021 4) 0.021

TRIAL 1, Reaction Time, s: 320, 152, 70, 30      Temperature C: 12, 25, 35, 45

TRIAL 2, Reaction Time, s: 305, 160, 66, 28      Temperature C: 12, 25, 35, 45

TRIAL 3, Reaction Time, s: 311, 156, 73, 33      Temperature C: 12, 25, 35, 45

Delta[S2O8-2] = 6.32*10-4 M

Reaction Rate for the determinations? (mol/ L*s)______________

Rate Constant, k?

ln(k)?

Reaction Temperature C?

Reaction Temperature K?

1/T, K^-1 ?

Slope of line?

Ea (J/mol) ?

ln A (y-intercept of line) ?

A, (1/M*s) ?

Homework Answers

Answer #1

Average time from Trial 1, 2 and 3 : 312, 156, 70, 30

Average Temperature C: 12, 25, 35, 45

Average Temperature K : 285, 298, 308, 318

1/T (K-1) : 0.0035, 0.0033, 0.0032, 0.0031

Rate (K) : -d1/2[I]/dt = -d[S2O8^2-]/dt : 0.000135, 0.000244, 0.000525, 0.0007

ln(K) : -8.91, -8.32, -7.55, -7.26

rate constant k = rate/[I-]^2.[S2O8^2-] = 0.000135/(0.021 x 0.042 x 0.042) = 3.64 M-2.s-1

Plot 1/T on x-axis and lnK on y-axis

slope = -Ea/R = -0.5720

Ea (J/mol) = 0.5720 x 8.314 = 4.75 J/mol

lnA = -6.5800

A = -0.152 M-1.s-1

Plot shown below

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