Question

Calculate the change in Gibbs free energy for each of the following sets of ?H?rxn, ?S?rxn,...

Calculate the change in Gibbs free energy for each of the following sets of ?H?rxn, ?S?rxn, and T.

Part A ?H?rxn=? 115 kJ ; ?S?rxn= 248 J/K ; T= 295 K

Part B ?H?rxn= 115 kJ ; ?S?rxn=? 248 J/K ; T= 295 K

Part C ?H?rxn=? 115 kJ ; ?S?rxn=? 248 J/K ; T= 295 K Express your answer using two significant figures.

Part D ?H?rxn=? 115 kJ ; ?S?rxn=? 248 J/K ; T= 565 K Express your answer using two significant figures.

Part E Predict whether or not the reaction in part A will be spontaneous at the temperature indicated.

Part F Predict whether or not the reaction in part B will be spontaneous at the temperature indicated.

Part G Predict whether or not the reaction in part C will be spontaneous at the temperature indicated.

Part H Predict whether or not the reaction in part D will be spontaneous at the temperature indicated.

Homework Answers

Answer #1

1. A.

= -115*10^3 - 295*248

= -188160 joules Or -188.160 KJ

E. is negative so the reaction is spontaneous.

B. 115*10^3 -295*(-248)

= 188160 Joules or 188.160 KJ

F. As is positive in reaction B so it is not a spontaneous reaction.

C. -115*10^3 - 295*(-248)

= -41840 Joules or -41.840 KJ

G. As is negative so reaction C is not spontaneous.

D. -115*10^3 - 565*(-248)

= -25120 Joules or -25.120 KJ

H. is negative in D so the reaction is spontaneous.

if satisfied please rate it thanks.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the change in Gibbs free energy for each of the following sets of ΔHrxn, ΔSrxn,...
Calculate the change in Gibbs free energy for each of the following sets of ΔHrxn, ΔSrxn, and T. Part A ΔH∘rxn= 90. kJ , ΔSrxn= 152 J/K , T= 303 K Express your answer using two significant figures. ΔG =   kJ   Part B ΔH∘rxn= 90. kJ , ΔSrxn= 152 J/K , T= 750 K Express your answer using two significant figures. ΔG =   kJ   Part C ΔH∘rxn= 90. kJ , ΔSrxn=− 152 J/K , T= 303 K Express your answer...
Calculate the change in Gibbs free energy for each of the following sets of ΔHrxn ∘,...
Calculate the change in Gibbs free energy for each of the following sets of ΔHrxn ∘, ΔS∘rxn, and T. 1) ΔH∘rxn=− 97 kJ , ΔS∘rxn=− 154 J/K , T= 310 K Express your answer using two significant figures. 2) ΔH∘rxn=− 97 kJ , ΔS∘rxn=− 154 J/K , T= 856 K 3) ΔH∘rxn= 97 kJ , ΔS∘rxn=− 154 J/K , T= 310 K 4) ΔH∘rxn=− 97 kJ , ΔS∘rxn= 154 J/K , T= 408 K
1) Calculate the amount of energy in kilojoules needed to change 207 g of water ice...
1) Calculate the amount of energy in kilojoules needed to change 207 g of water ice at −10 ∘C to steam at 125 ∘C. The following constants may be useful: Cm (ice)=36.57 J/(mol⋅∘C) Cm (water)=75.40 J/(mol⋅∘C) Cm (steam)=36.04 J/(mol⋅∘C) ΔHfus=+6.01 kJ/mol ΔHvap=+40.67 kJ/mol Express your answer with the appropriate units. 2) Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn= 90 kJ , ΔSrxn= 144 J/K , T= 304 K Express your answer using two...
Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn= 115 kJ...
Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn= 115 kJ , ΔS∘rxn=− 263 J/K , T= 301 K . ΔSuniv= J/K SubmitMy AnswersGive Up Part B ΔH∘rxn=− 115 kJ , ΔS∘rxn= 263 J/K , T= 301 K . ΔSuniv= J/K SubmitMy AnswersGive Up Part C ΔH∘rxn=− 115 kJ , ΔS∘rxn=− 263 J/K , T= 301 K . ΔSuniv= J/K SubmitMy AnswersGive Up Part D ΔH∘rxn=− 115 kJ , ΔS∘rxn=− 263 J/K , T= 557...
Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn= 117 kJ...
Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn= 117 kJ , ΔS∘rxn=− 263 J/K , T= 291 K . ΔSuniv= −1.3•102 J/K SubmitMy AnswersGive Up Incorrect; Try Again; 3 attempts remaining Part B ΔH∘rxn=− 117 kJ , ΔS∘rxn= 263 J/K , T= 291 K . ΔSuniv= J/K SubmitMy AnswersGive Up Part C ΔH∘rxn=− 117 kJ , ΔS∘rxn=− 263 J/K , T= 291 K. ΔSuniv= J/K SubmitMy AnswersGive Up Part D ΔH∘rxn=− 117 kJ ,...
± Gibbs Free Energy: Temperature Dependence Gibbs free energy (G) is a measure of the spontaneity...
± Gibbs Free Energy: Temperature Dependence Gibbs free energy (G) is a measure of the spontaneity of a chemical reaction. It is the chemical potential for a reaction, and is minimized at equilibrium. It is defined as G=H−TS where H is enthalpy, T is temperature, and S is entropy. The chemical reaction that causes aluminum to corrode in air is given by 4Al+3O2→2Al2O3 in which at 298 K ΔH∘rxn = −3352 kJ ΔS∘rxn = −625.1 J/K Part A What is...
� Gibbs Free Energy: Equilibrium Constant Nitric oxide, NO, also known as nitrogen monoxide, is one...
� Gibbs Free Energy: Equilibrium Constant Nitric oxide, NO, also known as nitrogen monoxide, is one of the primary contributors to air pollution, acid rain, and the depletion of the ozone layer. The reaction of oxygen and nitrogen to form nitric oxide in an automobile engine is N2(g)+O2(g)?2NO(g) The spontaneity of a reaction can be determined from the free energy change for the reaction, ?G?. A reaction is spontaneous when the free energy change is less than zero. A reaction...
Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn=− 89 kJ...
Given the values of ΔH∘rxn, ΔS∘rxn, and T below, determine ΔSuniv. Part A ΔH∘rxn=− 89 kJ , ΔSrxn=− 150 J/K , T= 310 K Express your answer using two significant figures. Part B ΔH∘rxn=− 89 kJ , ΔSrxn=− 150 J/K , T= 758 K Express your answer using one significant figure. Part C ΔH∘rxn=+ 89 kJ , ΔSrxn=− 150 J/K , T= 310 K Express your answer using two significant figures. Part D ΔH∘rxn=− 89 kJ , ΔSrxn=+ 150 J/K...
A. Using given data, calculate the change in Gibbs free energy for each of the following...
A. Using given data, calculate the change in Gibbs free energy for each of the following reactions. In each case indicate whether the reaction is spontaneous at 298K under standard conditions. 2H2O2(l)→2H2O(l)+O2(g) Gibbs free energy for H2O2(l) is -120.4kJ/mol Gibbs free energy for H2O(l) is -237.13kJ/mol B. A certain reaction has ΔH∘ = + 35.4 kJ and ΔS∘ = 85.0 J/K . Calculate ΔG∘ for the reaction at 298 K. Is the reaction spontaneous at 298K under standard conditions?
1)calculate the equilibrium constants at 25∘C for each reaction. Part A 2NO(g)+O2(g)⇌2NO2(g) Express your answer using...
1)calculate the equilibrium constants at 25∘C for each reaction. Part A 2NO(g)+O2(g)⇌2NO2(g) Express your answer using two significant figures. Part B N2(g)+O2(g)⇌2NO(g) Express your answer using two significant figures. 2) Calculate the change in Gibbs free energy for each of the following sets of ΔHrxn, ΔSrxn, and T. Part A ΔH∘rxn=+ 85 kJ , ΔSrxn=+ 155 J/K , T= 298 K Express your answer as an integer. Part B ΔH∘rxn=+ 85 kJ , ΔSrxn=+ 155 J/K , T= 753 K...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT