Question

The Ksp for silver sulfate (Ag2SO4) is 1.2 × 10-5. Calculate the molar solubility of silver...

The Ksp for silver sulfate (Ag2SO4) is 1.2 × 10-5. Calculate the molar solubility of silver sulfate in a solution of (4.5x10^-1) M K2SO4 Please clearly show your work and explain steps

Homework Answers

Answer #1

Given that Ksp of (Ag2SO4) = 1.2 × 10-5

[K2SO4 ] = [SO42-] = 4.5x10^-1 M = 0.45 M

Ag2SO4 -------------> 2Ag+ + SO42-

                                  2s             s                  s = molar solubility of silver sulfate

Ksp = [ 2Ag+]2 [ SO42-]

  1.2 × 10-5 = [2s]2 [ s + 0.45 ]

1.2 × 10-5 =   [ 4s3 + 1.8 s2 ]

Since s is very small, neglect s3 term

Hence,

1.2 × 10-5 =    1.8 s2

       s = 0.258 x 10-2 M

Therefore,

molar solubility of silver sulfate = 0.258 x 10-2 M

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