Ergosterol, a precursor of vitamin D, has δmax = 282 nm and molar absorptivity ε = 11,900 M-1cm-1.
1). What is the concentration of ergosterol in a solution whose
absorbance A = 6.5×10-2 with a
sample pathlength l = 1.00 cm.
2). What is the absorbance of a solution having a concentration of
ergosterol of 5.2×10-5 M with a sample
pathlength l = 1.00 cm?
Answer – 1) We are given, ε = 11900M-1.cm-1 , absorbance A = 6.5×10-2
pathlength l = 1.00 cm.
We know the Beer-Lambert law
A = ε * l* C
So, C = A / ε * l
= 6.5*10-2 / 11900M-1.cm-1* 1.00 cm
= 5.46*10-6 M
So, the concentration of ergosterol in a solution whose absorbance A = 6.5×10-2 with a sample pathlength l = 1.00 cm is 5.46*10-6 M
2) We are given, C =5.2*10-5 M, l = 1.00 cm
We know,
A = ε * l* C
= 11900M-1.cm-1* 1.00 cm *5.2*10-5 M
= 0.619
So, the absorbance of a solution having a concentration of ergosterol of 5.2×10-5 M with a sample pathlength l = 1.00 cm is 0.619
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