Question

A sample of crude oil contains 3.13 mM naphthalene, 12.0 mM methylnaphthalene, 23.8 mM dimethylnaphthalene, and...

A sample of crude oil contains 3.13 mM naphthalene, 12.0 mM methylnaphthalene, 23.8 mM dimethylnaphthalene, and 14.1 mM trimethylnaphthalene. What is the total number of moles of all the naphthalene compounds contained in 100.0 mL of crude oil? Do not enter your answer in scientific notation

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Answer #1

1mM = 0.001M


MOLARITY = NO.OF MOLES*1000/VOLUME OF THE SOLUTION
NO.OF MOLES = MOLARITY*VOLUME OF THE SOLUTION/1000


1) NO.OF MOLESOF NAPATHALENE = MOLARITY*VOLUME OF THE SOLUTION/1000

NO.OF MOLESOF NAPATHALENE = 0.00313*100/1000 =0.000313moles

2)
NO.OF MOLESOF methyl NAPATHALENE = MOLARITY*VOLUME OF THE SOLUTION/1000

NO.OF MOLESOF NAPATHALENE = 0.012*100/1000 =0.0.0012moles


3) NO.OF MOLESOF dimrthylNAPATHALENE = MOLARITY*VOLUME OF THE SOLUTION/1000

NO.OF MOLESOF diNAPATHALENE = 0.0238*100/1000 =0.00238moles


4) NO.OF MOLESOF trimethylNAPATHALENE = MOLARITY*VOLUME OF THE SOLUTION/1000

NO.OF MOLESOF tri methylNAPATHALENE = 0.0141*100/1000 =0.00141moles


total no.of moles= 0.000313 + 0.0012 +0.00238+0.00141
total no.of moles=0.005303moles

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