Question

When a metal was exposed to one photon of light at a frequency of 3.36x10^15s^-1, one electron was emitted with kinetic energy of 4.00x10^-19J. Calculate the work function of this metal in J (per photon). And what is the maximum number of electrons that could be ejected from this metal by a burst of photon (at the same other frequency) with a total energy of 7.27x10^-7J?

Answer 1

Solution :-

Lets calculate the energy of the photon

E= hv

   = 6.626*10^-34 J .s * 3.36*10^15 s-1

   = 2.226*10^-18 J

Lets calculate the energy difference of the photon and emitted electron

Difference in the energy = 2.226*10^-18 J – 4.00*10^-19 J = 1.826*10^-18 J

So the wavefunction of the metal = 1.826*10^-18 J

Now lets calculate the number of the electrons that can be ejectd from the metal surface with total energy of 7.27*10^-7 J

7.27*10^-17 J * 1 electron / 1.826*10^-18 J = 3.98*10^11 electrons

So the number of electrons that can be ejected = 3.98*10^17 electrons