Question

Which of the following substances would have the highest critical temperature? A. CH3Cl B. C2H6 C. F2 D. H2 E. CO2

The molar heats of sublimation and fusion of iodine are 62.3 kJ/mol and 15.3 kJ/mol, respectively. Calculate the molar heat of vaporization of liquid iodine. A. 77.6 kJ B. 47.0 kJ C. ─47.0 kJ D. ─77.6 kJ E. 4.07 kJ

Chlorine has a critical temperature of 144°C and a critical pressure of 77 atm. Under which of the following conditions would Cl2 most likely be a liquid? A. 125°C, 70 atm B. 125°C, 30 atm C. 150°C, 70 atm D. 150°C, 30 atm

(ANSWER, SHOW WORK, AND EXPLAIN FOR ALL PLEASE)

Answer 1

CH3Cl has got the highest critical temperature. This is the highest temperature above which a gas can't be liquified. Except for Methyl chloride, all others are gases. So first CH3Cl has to be converted into gas and then needs to be liquified.

The molar heat of vaproization= Heat of sublimation- heat of fusion = 62.3-15.3= 47 Kj

A gas can't be liquified above critical temperaure. But below critical temperauture and pressure it can exist as liquid and this is possible for 125 deg.c and 70 arm as well as 125 deg.c as well as 30 atm.