Question

refrigerant-134a at 100 kpa and 10 C flows through a refrigeration line. determine its specific volume in m3/kg

Answer 1

Refrigerant-134a is 1,1,2,2,tetraflouru ethane has molar mass is 102.03 g/mol

we find density d by formula   P = dRT /M  

P = 100 Kpa = 100 x 0.009869 atm = 0.9869 atm , R = 0.08206x , T = 10C = 10+273 = 274 K

0.9869 = ( d x 0.08206 x 274) / ( 102.03)

d = density = 4.47836 g /L

1L = 10^ -3 m3 ,

we had 4.47836 g per Liter

we had ( 4.47836 x 10^3 ) g per 1000 L or 1m3

mass in kg = 4.48 kg per m3

Thus for 1kg we have volume m3 = 1/4.48 = 0.2232 m3 per kg

specific volume = 0.2232 m3 /kg