If Potassium Iodide (KI) is reacted with oxone (KHSO5, 0.5KHSO4, 0.5K2SO4- a powerful oxidizing agent) what would be the products? Im thinking I2 will be produced but I have no clue how or why! Please help! Draw a picture if you can.
KI + 2 KHSO5- KHSO4- K2SO4 ---------> HOI + KOH + K2S2O8-KHSO4-K2SO4
hypoidousacid
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