Question

Find the Osmotic Pressure of a glucose solution if the mole fraction of glucose is 0.0118. I feel like I am missing information but this is all the info the problem gave me.

Answer 1

given

mole fraction of glucose = 0.0118

now

consider 1 mole of total solution

then

moles of glucose = 0.0118

moles of water = 1 - 0.0118

moles of water = 0.9882

now

mass = moles x molar mass

so

mass of water = 0.9882 x 18 = 17.7876

now

volume = mass / density

so

volume = 17.876 / 1 = 17.7876 ml

now

concentration (C) = molles of glucose x 1000 / volume

C = 0.0118 x 1000 / 17.7876

C = 0.6634 M

now

osmotic pressure = C x R x T

osmotic pressure = 0.6634 x 0.0821 x 298

osmotic pressure = 16.23 atm

so

the osmotic pressure is 16.23 atm