At a certain temperature, the equilibrium constant for the reaction below is 0.354.
cyclohexane ⇄ methylcyclopentane
If equilibrium is established in a mixture initially consisting of 74.3 g cyclohexane, what mass of methylcylopentane will be present? Report your answer to the nearest tenth of a gram without units.
cyclohexane(C6H14),molar mass=84.16 g/mol
methylcyclopentane(C5H9CH3),molar mass=84.16 g/mol
equilibrium constant=Kc=0.354=[methylcyclopentane]/[cyclohexane].......................(1)
[methylcyclopentane]=concentration of methylcyclopentane
[cyclohexane]=concentration of cyclohexane=74.3g/84.16 g/mol
[methylcyclopentane]=x g/84.16 g/mol
from (1),0.354=(x g/84.16 g/mol)/(74.3g/84.16 g/mol)=x/74.3g
0.354=x/74.3
x=0.354*74.3g=26.3022=26.3g =mass of methylcylopentane
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