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10 Amps of DC current is passed through a 10 OHM resistor in thermal contact with...

10 Amps of DC current is passed through a 10 OHM resistor in thermal contact with an 6 g block of Arbitrarium. The temperature of the block is raised by 6 K by this process. What is the specific heat of Arbitrarium?

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Answer #1

Heat generated from the resitor = I2.R.t

= (10)2(10)(39) [considering the time,t = 39]

= 39000 Joules

Which is equal to the heat energy transferred to the 6g block of Arbitrarium

Specific heat refers to the amount of heat required to raise unit mass of a substance's temperature by 1 degree.

The Specific Heat formula is:
  c = ΔQ / (m × ΔT)

Where:
  c: Specific Heat , in J/(kg.K)
  ΔQ: Heat required for the temperature change, in J
  ΔT: Temperature change, in K
  m: Mass of the object, in kg

Therefore,  c = 39000 / (0.006 × 6)

   = 1083.33 kJ/(kg.K)

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