Phosphorus pentachloride decomposes according to the chemical equation
PCl5 (g) <-------> PCl3 (g) + Cl2 (g) kc=1.80 at 250 C
A 0.296 mol sample of PCl5(g) is injected into an empty 3.80 L reaction vessel held at 250 °C. Calculate the concentrations of PCl5(g) and PCl3(g) at equilibrium.
Molarity of PCl5 = Number of moles of PCl5/Volume of container = 0.296/3.80 = 0.07789 M
PCl5 (g) <-------> PCl3 (g) + Cl2 (g)
Initial 0.07789 0 0
Final (0.07789-x) x x
Concentration of PCl3 = Concentration of Cl2 = 0.0747 M
Concentration of PCl5 = 0.07789 - 0.0747 = 0.00319 M
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