Question

In the acid base reaction shown between Glutaric Acid and NaOH: show calculation for the theoretical yield in grams of sodium glutamate if you react 1.23 grams of glutamic acid with 10.0 ml of 1.56 M NaOH solution.

Answer 1

Ans. Glutaric acid + NaOH = sodium glutarate + H2O

no. of moles of glutaric acid used = 1.23 / 132 = 0.0093 mol

moles of NaOH = Concentration * vol. in mL / 1000 = 1.56 * 10 / 1000 = 0.0156 moles

no. of moles of NaOH is used, hence glutaric acid will be consumed completely, and no. of moles of sodium glutarate will be equal to the no. of moles of glutaric acid

no. of moles of sodium glutarate formed = 0.0093 moles

theoretical yield = 0.0093 * molar mass of sodium glutarate = 0.0093 * 190 = 1.767 g