Question

1. The mass of an average blueberry is 0.71 g and the mass of an automobile is 2000 kg . Find the number of automobiles whose total mass is the same as 1.0 mol of blueberries. Express your answer to two significant figures. ??

2. A pure titanium cube has an edge length of 2.70 in . How many titanium atoms does it contain? Titanium has a density of 4.50 g/cm3 . Express your answer to three significant figures ??

3. A 6.94g sample of copper is contaminated with 0.81g of zinc. Suppose an atomic mass measurement was performed on this sample. ? What would be the measured atomic mass? Express your answer to four significant figures and include the appropriate units.

4. Calculate the mass of a single xenon atom (mXe=131.29amu) . Express the mass in grams to four significant figures??

5. What is the mass, in grams, of each of the following?

2.6 * 10^-3 mol Sb. ( 2 sig figures )

3.52 * 10^-2 mol Ba. ( 3 sig figures)

44.0 mol Xe. ( 3 sig figures)

1.5 mol W. ( 2 sig figures)

6. Using scanning tunneling microscopy, scientists at IBM wrote the initials of their company with 35 individual xenon atoms.

Calculate the total mass of these letters in grams . Express your answer using four significant figures .

7. Upon decomposition, one sample of magnesium fluoride produced 1.66 kg of magnesium and 2.58 kg of fluorine. A second sample produced 1.32 kg of magnesium. How much fluorine (in grams) did the second sample produce

Answer 1

1. The mass of an average blueberry is 0.71 g and the mass of an automobile is 2000 kg . Find the number of automobiles whose total mass is the same as 1.0 mol of blueberries. Express your answer to two significant figures. ??

m = 0.71 g

m = 2000 kg

first,find mass of blueberriues

1 mol = 6.022*10^23 berries

mass = 0.71 *(6.022*10^23) = 4.27562*10^23 grams

then

auto = 2000*10^3 = 2*10^6 grams per auto

(4.27562*10^23)/(2*10^6) = 2.13781*10^17 autos = 1 mol of berries

If only 2 sig fig is required

2.1*10^17 autos

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